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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4.     if (n == 1){
  5.         return 1;
  6.     }else if(n==0){
  7.     	return 0;
  8.     }
  9.     else {
  10.         return n+rec(n-2);
  11.     }
  12. }
  13. int main(void) {
  14.     int n = 11;
  15.     if( n%2 ==1){
  16.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  17.     }else{
  18.     printf("%d以下の正の偶数の和は%d\n", n, rec(n));	
  19.     }
  20. 	return 0;
  21. }
Success #stdin #stdout 0.01s 5320KB
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11以下の正の奇数の和は36
https://ideone.com/zDMel3
language:
C (gcc 8.3)
created:
11 days ago
visibility:
public

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