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  1. #include <iostream>
  2. #include <cmath>
  3.  
  4. using namespace std;
  5.  
  6. int main() {
  7.  
  8.     /* ===== PRZYPADEK 1 =====
  9.        3x^2 + 4x + 5 = 0
  10.     */
  11.     {
  12.         double a = 3.0;
  13.         double b = 4.0;
  14.         double c = 5.0;
  15.  
  16.         double delta = b * b - 4 * a * c;
  17.         cout << "Rownanie: 3x^2 + 4x + 5 = 0" << endl;
  18.         cout << "Delta = " << delta << endl;
  19.  
  20.         if (delta < 0) {
  21.             cout << "Brak pierwiastkow rzeczywistych." << endl;
  22.         }
  23.         cout << endl;
  24.     }
  25.  
  26.     /* ===== PRZYPADEK 2 =====
  27.        x^2 + 10000x + 1 = 0
  28.        float + Vieta
  29.     */
  30.     {
  31.         float a = 1.0f;
  32.         float b = 10000.0f;
  33.         float c = 1.0f;
  34.  
  35.         float delta = b * b - 4 * a * c;
  36.         cout << "Rownanie: x^2 + 10000x + 1 = 0" << endl;
  37.         cout << "Delta = " << delta << endl;
  38.  
  39.         if (delta > 0) {
  40.             // liczymy tylko jeden pierwiastek klasycznie
  41.             float x1 = (-b - sqrt(delta)) / (2 * a);
  42.  
  43.             // drugi z wzoru Viety
  44.             float x2 = (c / a) / x1;
  45.  
  46.             cout << "Pierwiastki (delta + Vieta):" << endl;
  47.             cout << "x1 = " << x1 << endl;
  48.             cout << "x2 = " << x2 << endl;
  49.         }
  50.  
  51.         cout << endl;
  52.     }
  53.  
  54.     return 0;
  55. }
  56.  
  57.  
Success #stdin #stdout 0.01s 5288KB
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Standard input is empty
stdout
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Rownanie: 3x^2 + 4x + 5 = 0
Delta = -44
Brak pierwiastkow rzeczywistych.

Rownanie: x^2 + 10000x + 1 = 0
Delta = 1e+08
Pierwiastki (delta + Vieta):
x1 = -10000
x2 = -0.0001
https://ideone.com/mdJ0zc
language:
C++ (gcc 8.3)
created:
2 days ago
visibility:
public

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