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  1. #include <stdio.h>
  2.  
  3. // 正の奇数 n 以下の奇数の和を求める関数
  4. int rec(int n){
  5.     if (n == 1){
  6.         return 1;          
  7.     }
  8.     else{
  9.         return n + rec(n-2);  
  10.     }
  11. }
  12.  
  13. int main(void) {
  14.     int n = 11;
  15.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  16.     return 0;
  17. }
Success #stdin #stdout 0s 5304KB
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11以下の正の奇数の和は36
https://ideone.com/kjDjg7
language:
C (gcc 8.3)
created:
11 days ago
visibility:
public

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