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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4.     if (n == 1){
  5.         return 1;
  6.     }
  7.     if (n==0){
  8.     	return 0;}
  9.  
  10.     else{
  11.         return n=n+rec(n-2);
  12.     }
  13. }
  14. int main(void) {
  15.     int n = 12;
  16.     if(n%2==0){
  17.     	printf("%d以下の正の偶数の和は%d\n", n, rec(n));
  18.     }
  19.     else
  20.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  21. 	return 0;
  22. }
Success #stdin #stdout 0.01s 5316KB
comments (?)
stdin 
Standard input is empty
stdout 
12以下の正の偶数の和は42
https://ideone.com/TUzWYE
language:
C (gcc 8.3)
created:
11 days ago
visibility:
public

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