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  1. #include <stdio.h>
  2. //再帰を用いて1からnまでの二乗和1^2 + 2^2 + 3^2 + ... + n^2を計算する
  3.  
  4. int main(void) {
  5.     int n,an;
  6.      n=1;
  7.      an=4;
  8.     for(int i=1; i<=n; i++){
  9.     	an = n*n;
  10.  
  11.     }
  12.  
  13.     printf("1から%dまでの二乗和の値は%d\n", an);
  14. 	return 0;
  15. }
  16.  
  17.  
Success #stdin #stdout 0s 5324KB
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1から1までの二乗和の値は-19324560
https://ideone.com/OaiAak
language:
C (gcc 8.3)
created:
11 days ago
visibility:
public

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