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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4.     if (n == 1){
  5.         return 1;
  6.     }else if(n==0){
  7.     	return 0;
  8.     }
  9.     else{
  10.         return n+rec(n-2);
  11.     }
  12. }
  13. int main(void) {
  14.     int n = 12;
  15.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  16. 	return 0;
  17. }
  18.  
Success #stdin #stdout 0s 5320KB
comments (?)
stdin 
Standard input is empty
stdout 
12以下の正の奇数の和は42
https://ideone.com/NvLTdV
language:
C (gcc 8.3)
created:
11 days ago
visibility:
public

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