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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec()
  4. 	{
  5. 	int n=2;
  6.     if (n == 2){
  7.         return 2;
  8.     }
  9.     else{
  10.         return n+rec(n-2);
  11.     }
  12. }
  13. int main(void) {
  14.     int n = 11;
  15.     printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  16. 	return 0;
  17. }
Success #stdin #stdout 0.01s 5308KB
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11以下の正の奇数の和は2
https://ideone.com/AK2CRQ
language:
C (gcc 8.3)
created:
11 days ago
visibility:
public

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