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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4.    if (n <= 0) return 0;   
  5.     if (n == 1) return 1;  
  6.  
  7.     if (n % 2 == 0) {
  8.         return rec(n - 1);
  9.     }
  10.     else{
  11.         return rec(n-2) + n;
  12.     }
  13. }
  14. int main(void) {
  15.     int n = 13;
  16.     printf("%d以下の正の偶数の和は%d\n", n, rec(n));
  17. 	return 0;
  18. }
Success #stdin #stdout 0.01s 5284KB
comments (?)
stdin 
Standard input is empty
stdout 
13以下の正の偶数の和は49
https://ideone.com/6Ao44B
language:
C (gcc 8.3)
created:
11 days ago
visibility:
public

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